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60451213441 is a prime number
BaseRepresentation
bin111000010011001011…
…000101000010000001
312210000221121211020011
4320103023011002001
51442301002312231
643434303144521
74240015556533
oct702313050201
9183027554204
1060451213441
1123701152433
12b870ba5141
1359150902a8
142cd6789853
15188c1809b1
hexe132c5081

60451213441 has 2 divisors, whose sum is σ = 60451213442. Its totient is φ = 60451213440.

The previous prime is 60451213397. The next prime is 60451213469. The reversal of 60451213441 is 14431215406.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31009801216 + 29441412225 = 176096^2 + 171585^2 .

It is a cyclic number.

It is not a de Polignac number, because 60451213441 - 29 = 60451212929 is a prime.

It is not a weakly prime, because it can be changed into another prime (60451213541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30225606720 + 30225606721.

It is an arithmetic number, because the mean of its divisors is an integer number (30225606721).

Almost surely, 260451213441 is an apocalyptic number.

It is an amenable number.

60451213441 is a deficient number, since it is larger than the sum of its proper divisors (1).

60451213441 is an equidigital number, since it uses as much as digits as its factorization.

60451213441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 60451213441 its reverse (14431215406), we get a palindrome (74882428847).

The spelling of 60451213441 in words is "sixty billion, four hundred fifty-one million, two hundred thirteen thousand, four hundred forty-one".