Base | Representation |
---|---|
bin | 111000010011001011… |
… | …000101000010000001 |
3 | 12210000221121211020011 |
4 | 320103023011002001 |
5 | 1442301002312231 |
6 | 43434303144521 |
7 | 4240015556533 |
oct | 702313050201 |
9 | 183027554204 |
10 | 60451213441 |
11 | 23701152433 |
12 | b870ba5141 |
13 | 59150902a8 |
14 | 2cd6789853 |
15 | 188c1809b1 |
hex | e132c5081 |
60451213441 has 2 divisors, whose sum is σ = 60451213442. Its totient is φ = 60451213440.
The previous prime is 60451213397. The next prime is 60451213469. The reversal of 60451213441 is 14431215406.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31009801216 + 29441412225 = 176096^2 + 171585^2 .
It is a cyclic number.
It is not a de Polignac number, because 60451213441 - 29 = 60451212929 is a prime.
It is not a weakly prime, because it can be changed into another prime (60451213541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30225606720 + 30225606721.
It is an arithmetic number, because the mean of its divisors is an integer number (30225606721).
Almost surely, 260451213441 is an apocalyptic number.
It is an amenable number.
60451213441 is a deficient number, since it is larger than the sum of its proper divisors (1).
60451213441 is an equidigital number, since it uses as much as digits as its factorization.
60451213441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 60451213441 its reverse (14431215406), we get a palindrome (74882428847).
The spelling of 60451213441 in words is "sixty billion, four hundred fifty-one million, two hundred thirteen thousand, four hundred forty-one".
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