Base | Representation |
---|---|
bin | 101011111111111110001… |
… | …1010111111111000011111 |
3 | 210102010000112010110201222 |
4 | 1113333330122333320133 |
5 | 1243034234000440221 |
6 | 20510023050323555 |
7 | 1162620406134461 |
oct | 127777432777037 |
9 | 23363015113658 |
10 | 6047253921311 |
11 | 1a21698206989 |
12 | 817bb91295bb |
13 | 34b33b201795 |
14 | 16c98d934131 |
15 | a74826e49ab |
hex | 57ffc6bfe1f |
6047253921311 has 4 divisors (see below), whose sum is σ = 6132426511824. Its totient is φ = 5962081330800.
The previous prime is 6047253921277. The next prime is 6047253921337. The reversal of 6047253921311 is 1131293527406.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6047253921311 is a prime.
It is a super-2 number, since 2×60472539213112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6047253920311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42586295150 + ... + 42586295291.
It is an arithmetic number, because the mean of its divisors is an integer number (1533106627956).
Almost surely, 26047253921311 is an apocalyptic number.
6047253921311 is a deficient number, since it is larger than the sum of its proper divisors (85172590513).
6047253921311 is an equidigital number, since it uses as much as digits as its factorization.
6047253921311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85172590512.
The product of its (nonzero) digits is 272160, while the sum is 44.
The spelling of 6047253921311 in words is "six trillion, forty-seven billion, two hundred fifty-three million, nine hundred twenty-one thousand, three hundred eleven".
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