6050055000433 has 2 divisors, whose sum is σ = 6050055000434. Its totient is φ = 6050055000432.

The previous prime is 6050055000421. The next prime is 6050055000469. The reversal of 6050055000433 is 3340005500506.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3057542507889 + 2992512492544 = 1748583^2 + 1729888^2 .

It is a cyclic number.

It is not a de Polignac number, because 6050055000433 - 2⁵ = 6050055000401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 6050055000395 and 6050055000404.

It is not a weakly prime, because it can be changed into another prime (6050055007433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3025027500216 + 3025027500217.

It is an arithmetic number, because the mean of its divisors is an integer number (3025027500217).

Almost surely, 2^{6050055000433} is an apocalyptic number.

It is an amenable number.

6050055000433 is a deficient number, since it is larger than the sum of its proper divisors (1).

6050055000433 is an equidigital number, since it uses as much as digits as its factorization.

6050055000433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 6050055000433 in words is "six trillion, fifty billion, fifty-five million, four hundred thirty-three", and thus it is an aban number.