Base | Representation |
---|---|
bin | 10001100111001010010… |
… | …01111000011101010011 |
3 | 2010211222020122211100002 |
4 | 20303211021320131103 |
5 | 34403311314310301 |
6 | 1141555242120215 |
7 | 61501635040406 |
oct | 10634511703523 |
9 | 2124866584302 |
10 | 605139994451 |
11 | 2137028294a3 |
12 | 993441b006b |
13 | 450ab7c3a45 |
14 | 21408b87d3d |
15 | 10b1b22916b |
hex | 8ce5278753 |
605139994451 has 2 divisors, whose sum is σ = 605139994452. Its totient is φ = 605139994450.
The previous prime is 605139994399. The next prime is 605139994477. The reversal of 605139994451 is 154499931506.
605139994451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 605139994451 - 210 = 605139993427 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (605139994051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302569997225 + 302569997226.
It is an arithmetic number, because the mean of its divisors is an integer number (302569997226).
Almost surely, 2605139994451 is an apocalyptic number.
605139994451 is a deficient number, since it is larger than the sum of its proper divisors (1).
605139994451 is an equidigital number, since it uses as much as digits as its factorization.
605139994451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5248800, while the sum is 56.
The spelling of 605139994451 in words is "six hundred five billion, one hundred thirty-nine million, nine hundred ninety-four thousand, four hundred fifty-one".
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