Base | Representation |
---|---|
bin | 11011101111101001000000… |
… | …11101100001101000010001 |
3 | 22000000112220111000001202001 |
4 | 31313310200131201220101 |
5 | 30444044104043104023 |
6 | 333431510112154001 |
7 | 15564603300224455 |
oct | 1567644035415021 |
9 | 260015814001661 |
10 | 61010555050513 |
11 | 18492481869742 |
12 | 6a14307538901 |
13 | 2807369822743 |
14 | 110ccd8908665 |
15 | 70c057cb66ad |
hex | 377d20761a11 |
61010555050513 has 2 divisors, whose sum is σ = 61010555050514. Its totient is φ = 61010555050512.
The previous prime is 61010555050457. The next prime is 61010555050663. The reversal of 61010555050513 is 31505055501016.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 61009721400384 + 833650129 = 7810872^2 + 28873^2 .
It is a cyclic number.
It is not a de Polignac number, because 61010555050513 - 237 = 60873116097041 is a prime.
It is not a weakly prime, because it can be changed into another prime (61010555050213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30505277525256 + 30505277525257.
It is an arithmetic number, because the mean of its divisors is an integer number (30505277525257).
Almost surely, 261010555050513 is an apocalyptic number.
It is an amenable number.
61010555050513 is a deficient number, since it is larger than the sum of its proper divisors (1).
61010555050513 is an equidigital number, since it uses as much as digits as its factorization.
61010555050513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56250, while the sum is 37.
The spelling of 61010555050513 in words is "sixty-one trillion, ten billion, five hundred fifty-five million, fifty thousand, five hundred thirteen".
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