Base | Representation |
---|---|
bin | 101100011001000010111… |
… | …1101100000111111111001 |
3 | 210121021000020000100000112 |
4 | 1120302011331200333321 |
5 | 1244430023332242433 |
6 | 20550450201314105 |
7 | 1166534654211356 |
oct | 130620575407771 |
9 | 23537006010015 |
10 | 6101101055993 |
11 | 1a4250a544189 |
12 | 826526495935 |
13 | 35343cccca58 |
14 | 17141b18562d |
15 | a8a84bb6348 |
hex | 58c85f60ff9 |
6101101055993 has 2 divisors, whose sum is σ = 6101101055994. Its totient is φ = 6101101055992.
The previous prime is 6101101055981. The next prime is 6101101056041. The reversal of 6101101055993 is 3995501011016.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5698380088384 + 402720967609 = 2387128^2 + 634603^2 .
It is a cyclic number.
It is not a de Polignac number, because 6101101055993 - 24 = 6101101055977 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6101101055993.
It is not a weakly prime, because it can be changed into another prime (6101101052993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3050550527996 + 3050550527997.
It is an arithmetic number, because the mean of its divisors is an integer number (3050550527997).
Almost surely, 26101101055993 is an apocalyptic number.
It is an amenable number.
6101101055993 is a deficient number, since it is larger than the sum of its proper divisors (1).
6101101055993 is an equidigital number, since it uses as much as digits as its factorization.
6101101055993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36450, while the sum is 41.
The spelling of 6101101055993 in words is "six trillion, one hundred one billion, one hundred one million, fifty-five thousand, nine hundred ninety-three".
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