Base | Representation |
---|---|
bin | 111000110110101101… |
… | …000001100101000001 |
3 | 12211120111021220111112 |
4 | 320312231001211001 |
5 | 2000011103033003 |
6 | 44013355453105 |
7 | 4260544420325 |
oct | 706655014501 |
9 | 184514256445 |
10 | 61047314753 |
11 | 23987688147 |
12 | b9b8757195 |
13 | 59ab722469 |
14 | 2d519d9985 |
15 | 18c467d3d8 |
hex | e36b41941 |
61047314753 has 2 divisors, whose sum is σ = 61047314754. Its totient is φ = 61047314752.
The previous prime is 61047314749. The next prime is 61047314821. The reversal of 61047314753 is 35741374016.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42647206144 + 18400108609 = 206512^2 + 135647^2 .
It is a cyclic number.
It is not a de Polignac number, because 61047314753 - 22 = 61047314749 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 61047314753.
It is not a weakly prime, because it can be changed into another prime (61047314953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30523657376 + 30523657377.
It is an arithmetic number, because the mean of its divisors is an integer number (30523657377).
Almost surely, 261047314753 is an apocalyptic number.
It is an amenable number.
61047314753 is a deficient number, since it is larger than the sum of its proper divisors (1).
61047314753 is an equidigital number, since it uses as much as digits as its factorization.
61047314753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 41.
Adding to 61047314753 its reverse (35741374016), we get a palindrome (96788688769).
The spelling of 61047314753 in words is "sixty-one billion, forty-seven million, three hundred fourteen thousand, seven hundred fifty-three".
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