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61055001113 is a prime number
BaseRepresentation
bin111000110111001010…
…010110001000011001
312211121000202102012112
4320313022112020121
52000020040013423
644014232322105
74260666642461
oct706712261031
9184530672175
1061055001113
1123990a58007
12b9bb243335
1359b01b3bc2
142d52a3aba1
1518c519aa78
hexe37296219

61055001113 has 2 divisors, whose sum is σ = 61055001114. Its totient is φ = 61055001112.

The previous prime is 61055001107. The next prime is 61055001131. The reversal of 61055001113 is 31110055016.

Together with next prime (61055001131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60933935104 + 121066009 = 246848^2 + 11003^2 .

It is a cyclic number.

It is not a de Polignac number, because 61055001113 - 222 = 61050806809 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (61055001193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30527500556 + 30527500557.

It is an arithmetic number, because the mean of its divisors is an integer number (30527500557).

Almost surely, 261055001113 is an apocalyptic number.

It is an amenable number.

61055001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

61055001113 is an equidigital number, since it uses as much as digits as its factorization.

61055001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 61055001113 its reverse (31110055016), we get a palindrome (92165056129).

The spelling of 61055001113 in words is "sixty-one billion, fifty-five million, one thousand, one hundred thirteen".