Base | Representation |
---|---|
bin | 11011110010111011011110… |
… | …11111111000111101100100 |
3 | 22000102100120022100102102020 |
4 | 31321131233133320331210 |
5 | 31002422012324021012 |
6 | 333555434334543140 |
7 | 15606013361302041 |
oct | 1571355737707544 |
9 | 260370508312366 |
10 | 61123550220132 |
11 | 18526396680044 |
12 | 6a321a1367ab0 |
13 | 2814c0670235a |
14 | 11145777d81c8 |
15 | 70ee6cceba8c |
hex | 37976f7f8f64 |
61123550220132 has 24 divisors (see below), whose sum is σ = 146100193210272. Its totient is φ = 19877577307200.
The previous prime is 61123550220097. The next prime is 61123550220151. The reversal of 61123550220132 is 23102205532116.
It is a junction number, because it is equal to n+sod(n) for n = 61123550220093 and 61123550220102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62117428594 + ... + 62117429577.
It is an arithmetic number, because the mean of its divisors is an integer number (6087508050428).
Almost surely, 261123550220132 is an apocalyptic number.
It is an amenable number.
61123550220132 is an abundant number, since it is smaller than the sum of its proper divisors (84976642990140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
61123550220132 is a wasteful number, since it uses less digits than its factorization.
61123550220132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124234858219 (or 124234858217 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 61123550220132 its reverse (23102205532116), we get a palindrome (84225755752248).
The spelling of 61123550220132 in words is "sixty-one trillion, one hundred twenty-three billion, five hundred fifty million, two hundred twenty thousand, one hundred thirty-two".
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