Base | Representation |
---|---|
bin | 11011110011011110000011… |
… | …11101100111011001011010 |
3 | 22000111010111000122111201022 |
4 | 31321233001331213121122 |
5 | 31003223022041112102 |
6 | 334012144344522442 |
7 | 15610241400450113 |
oct | 1571570175473132 |
9 | 260433430574638 |
10 | 61142113613402 |
11 | 18533252188178 |
12 | 6a35902180422 |
13 | 28168a4582323 |
14 | 1115418d9d20a |
15 | 7106a78915a2 |
hex | 379bc1f6765a |
61142113613402 has 4 divisors (see below), whose sum is σ = 91713170420106. Its totient is φ = 30571056806700.
The previous prime is 61142113613353. The next prime is 61142113613417. The reversal of 61142113613402 is 20431631124116.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 60253130519521 + 888983093881 = 7762289^2 + 942859^2 .
It is a super-3 number, since 3×611421136134023 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15285528403349 + ... + 15285528403352.
Almost surely, 261142113613402 is an apocalyptic number.
61142113613402 is a deficient number, since it is larger than the sum of its proper divisors (30571056806704).
61142113613402 is a wasteful number, since it uses less digits than its factorization.
61142113613402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30571056806703.
The product of its (nonzero) digits is 20736, while the sum is 35.
Adding to 61142113613402 its reverse (20431631124116), we get a palindrome (81573744737518).
The spelling of 61142113613402 in words is "sixty-one trillion, one hundred forty-two billion, one hundred thirteen million, six hundred thirteen thousand, four hundred two".
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