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61142113613417 is a prime number
BaseRepresentation
bin11011110011011110000011…
…11101100111011001101001
322000111010111000122111201212
431321233001331213121221
531003223022041112132
6334012144344522505
715610241400450134
oct1571570175473151
9260433430574655
1061142113613417
1118533252188191
126a35902180435
1328168a4582335
141115418d9d21b
157106a78915b2
hex379bc1f67669

61142113613417 has 2 divisors, whose sum is σ = 61142113613418. Its totient is φ = 61142113613416.

The previous prime is 61142113613353. The next prime is 61142113613461. The reversal of 61142113613417 is 71431631124116.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47811845281321 + 13330268332096 = 6914611^2 + 3651064^2 .

It is a cyclic number.

It is not a de Polignac number, because 61142113613417 - 26 = 61142113613353 is a prime.

It is a super-3 number, since 3×611421136134173 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (61142113613717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30571056806708 + 30571056806709.

It is an arithmetic number, because the mean of its divisors is an integer number (30571056806709).

Almost surely, 261142113613417 is an apocalyptic number.

It is an amenable number.

61142113613417 is a deficient number, since it is larger than the sum of its proper divisors (1).

61142113613417 is an equidigital number, since it uses as much as digits as its factorization.

61142113613417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72576, while the sum is 41.

The spelling of 61142113613417 in words is "sixty-one trillion, one hundred forty-two billion, one hundred thirteen million, six hundred thirteen thousand, four hundred seventeen".