611432534010433 has 2 divisors, whose sum is σ = 611432534010434. Its totient is φ = 611432534010432.

The previous prime is 611432534010413. The next prime is 611432534010479. The reversal of 611432534010433 is 334010435234116.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 547789905727744 + 63642628282689 = 23404912^2 + 7977633^2 .

It is a cyclic number.

It is not a de Polignac number, because 611432534010433 - 2¹⁷ = 611432533879361 is a prime.

It is not a weakly prime, because it can be changed into another prime (611432534010413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305716267005216 + 305716267005217.

It is an arithmetic number, because the mean of its divisors is an integer number (305716267005217).

Almost surely, 2^{611432534010433} is an apocalyptic number.

It is an amenable number.

611432534010433 is a deficient number, since it is larger than the sum of its proper divisors (1).

611432534010433 is an equidigital number, since it uses as much as digits as its factorization.

611432534010433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 611432534010433 its reverse (334010435234116), we get a palindrome (945442969244549).

The spelling of 611432534010433 in words is "six hundred eleven trillion, four hundred thirty-two billion, five hundred thirty-four million, ten thousand, four hundred thirty-three".