Base | Representation |
---|---|
bin | 111000111100011111… |
… | …000011100011100011 |
3 | 12211211020211002101011 |
4 | 320330133003203203 |
5 | 2000210421104011 |
6 | 44031142521351 |
7 | 4263133053223 |
oct | 707437034343 |
9 | 184736732334 |
10 | 61144316131 |
11 | 23a27410778 |
12 | ba25136257 |
13 | 59c5856122 |
14 | 2d6084a083 |
15 | 18cce3e621 |
hex | e3c7c38e3 |
61144316131 has 2 divisors, whose sum is σ = 61144316132. Its totient is φ = 61144316130.
The previous prime is 61144316113. The next prime is 61144316137. The reversal of 61144316131 is 13161344116.
Together with previous prime (61144316113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61144316131 - 25 = 61144316099 is a prime.
It is a super-2 number, since 2×611443161312 (a number of 22 digits) contains 22 as substring.
It is a zygodrome in base 2.
It is a junction number, because it is equal to n+sod(n) for n = 61144316093 and 61144316102.
It is not a weakly prime, because it can be changed into another prime (61144316137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30572158065 + 30572158066.
It is an arithmetic number, because the mean of its divisors is an integer number (30572158066).
Almost surely, 261144316131 is an apocalyptic number.
61144316131 is a deficient number, since it is larger than the sum of its proper divisors (1).
61144316131 is an equidigital number, since it uses as much as digits as its factorization.
61144316131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 31.
The spelling of 61144316131 in words is "sixty-one billion, one hundred forty-four million, three hundred sixteen thousand, one hundred thirty-one".
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