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612412315552057 is a prime number
BaseRepresentation
bin1000101100111111000101101…
…0100001100100100100111001
32222022101001020020102111220011
42023033301122201210210321
51120232230410240131212
610010254200035501521
7242665221040532236
oct21317613241444471
92868331206374804
10612412315552057
11168151671633739
12588297394578a1
1320394306183b47
14ab32cb28cc78d
154ac03b2cd94a7
hex22cfc5a864939

612412315552057 has 2 divisors, whose sum is σ = 612412315552058. Its totient is φ = 612412315552056.

The previous prime is 612412315552027. The next prime is 612412315552151. The reversal of 612412315552057 is 750255513214216.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 555806840709136 + 56605474842921 = 23575556^2 + 7523661^2 .

It is a cyclic number.

It is not a de Polignac number, because 612412315552057 - 215 = 612412315519289 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 612412315552057.

It is not a weakly prime, because it can be changed into another prime (612412315552007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306206157776028 + 306206157776029.

It is an arithmetic number, because the mean of its divisors is an integer number (306206157776029).

Almost surely, 2612412315552057 is an apocalyptic number.

It is an amenable number.

612412315552057 is a deficient number, since it is larger than the sum of its proper divisors (1).

612412315552057 is an equidigital number, since it uses as much as digits as its factorization.

612412315552057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520000, while the sum is 49.

The spelling of 612412315552057 in words is "six hundred twelve trillion, four hundred twelve billion, three hundred fifteen million, five hundred fifty-two thousand, fifty-seven".