Base | Representation |
---|---|
bin | 11011110111010000101000… |
… | …00000011110010100101001 |
3 | 22000221120121122220022222121 |
4 | 31323220110000132110221 |
5 | 31012341222303111012 |
6 | 334152042441151241 |
7 | 15622531453105336 |
oct | 1573502400362451 |
9 | 260846548808877 |
10 | 61272339113257 |
11 | 185834a9076718 |
12 | 6a56ba648b521 |
13 | 2825c5909ba0c |
14 | 111b8503a798d |
15 | 713c7a3e9a07 |
hex | 37ba1401e529 |
61272339113257 has 2 divisors, whose sum is σ = 61272339113258. Its totient is φ = 61272339113256.
The previous prime is 61272339113231. The next prime is 61272339113263. The reversal of 61272339113257 is 75231193327216.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56978508624921 + 4293830488336 = 7548411^2 + 2072156^2 .
It is a cyclic number.
It is not a de Polignac number, because 61272339113257 - 211 = 61272339111209 is a prime.
It is not a weakly prime, because it can be changed into another prime (61272369113257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30636169556628 + 30636169556629.
It is an arithmetic number, because the mean of its divisors is an integer number (30636169556629).
Almost surely, 261272339113257 is an apocalyptic number.
It is an amenable number.
61272339113257 is a deficient number, since it is larger than the sum of its proper divisors (1).
61272339113257 is an equidigital number, since it uses as much as digits as its factorization.
61272339113257 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2857680, while the sum is 52.
The spelling of 61272339113257 in words is "sixty-one trillion, two hundred seventy-two billion, three hundred thirty-nine million, one hundred thirteen thousand, two hundred fifty-seven".
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