612999403 has 2 divisors, whose sum is σ = 612999404. Its totient is φ = 612999402.

The previous prime is 612999371. The next prime is 612999407. The reversal of 612999403 is 304999216.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 612999403 - 2⁵ = 612999371 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 612999403.

It is not a weakly prime, because it can be changed into another prime (612999407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306499701 + 306499702.

It is an arithmetic number, because the mean of its divisors is an integer number (306499702).

Almost surely, 2^612999403 is an apocalyptic number.

612999403 is a deficient number, since it is larger than the sum of its proper divisors (1).

612999403 is an equidigital number, since it uses as much as digits as its factorization.

612999403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 104976, while the sum is 43.

The square root of 612999403 is about 24758.8247499755. The cubic root of 612999403 is about 849.4803758324.

The spelling of 612999403 in words is "six hundred twelve million, nine hundred ninety-nine thousand, four hundred three".