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61330824482371 is a prime number
BaseRepresentation
bin11011111000111101100100…
…00000011100111001000011
322001011011120121102220202121
431330132302000130321003
531014321012031413441
6334234554121425111
715630002001410503
oct1574366200347103
9261134517386677
1061330824482371
11185a6290590114
126a663a903b197
13282b619ab32c2
1411205dba29a03
1571554ebb2dd1
hex37c7b201ce43

61330824482371 has 2 divisors, whose sum is σ = 61330824482372. Its totient is φ = 61330824482370.

The previous prime is 61330824482341. The next prime is 61330824482399. The reversal of 61330824482371 is 17328442803316.

61330824482371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 61330824482371 - 25 = 61330824482339 is a prime.

It is a super-2 number, since 2×613308244823712 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (61330824482341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30665412241185 + 30665412241186.

It is an arithmetic number, because the mean of its divisors is an integer number (30665412241186).

Almost surely, 261330824482371 is an apocalyptic number.

61330824482371 is a deficient number, since it is larger than the sum of its proper divisors (1).

61330824482371 is an equidigital number, since it uses as much as digits as its factorization.

61330824482371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4644864, while the sum is 52.

The spelling of 61330824482371 in words is "sixty-one trillion, three hundred thirty billion, eight hundred twenty-four million, four hundred eighty-two thousand, three hundred seventy-one".