Base | Representation |
---|---|
bin | 10001110110011000111… |
… | …00011100001000111011 |
3 | 2011122002000001121012011 |
4 | 20323030130130020323 |
5 | 40022032213112022 |
6 | 1145430404430351 |
7 | 62211345400306 |
oct | 10731434341073 |
9 | 2148060047164 |
10 | 613315363387 |
11 | 217118596151 |
12 | 9aa460a83b7 |
13 | 45ab2478b5c |
14 | 21982861b3d |
15 | 10e48d15977 |
hex | 8ecc71c23b |
613315363387 has 2 divisors, whose sum is σ = 613315363388. Its totient is φ = 613315363386.
The previous prime is 613315363343. The next prime is 613315363399. The reversal of 613315363387 is 783363513316.
613315363387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 613315363387 - 231 = 611167879739 is a prime.
It is a super-2 number, since 2×6133153633872 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 613315363387.
It is not a weakly prime, because it can be changed into another prime (613315367387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306657681693 + 306657681694.
It is an arithmetic number, because the mean of its divisors is an integer number (306657681694).
Almost surely, 2613315363387 is an apocalyptic number.
613315363387 is a deficient number, since it is larger than the sum of its proper divisors (1).
613315363387 is an equidigital number, since it uses as much as digits as its factorization.
613315363387 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2449440, while the sum is 49.
The spelling of 613315363387 in words is "six hundred thirteen billion, three hundred fifteen million, three hundred sixty-three thousand, three hundred eighty-seven".
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