Base | Representation |
---|---|
bin | 11011111010000011010010… |
… | …00100100010100011011001 |
3 | 22001021202012020112210112221 |
4 | 31331001221010202203121 |
5 | 31020424141403214113 |
6 | 334304104250504041 |
7 | 15632465403122104 |
oct | 1575015104424331 |
9 | 261252166483487 |
10 | 61368255523033 |
11 | 18610149414a68 |
12 | 6a716b4735021 |
13 | 2832003870484 |
14 | 112234cd5573b |
15 | 7164e0d9b98d |
hex | 37d0691228d9 |
61368255523033 has 2 divisors, whose sum is σ = 61368255523034. Its totient is φ = 61368255523032.
The previous prime is 61368255523009. The next prime is 61368255523111. The reversal of 61368255523033 is 33032555286316.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58012793591769 + 3355461931264 = 7616613^2 + 1831792^2 .
It is a cyclic number.
It is not a de Polignac number, because 61368255523033 - 29 = 61368255522521 is a prime.
It is a super-3 number, since 3×613682555230333 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (61368255563033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30684127761516 + 30684127761517.
It is an arithmetic number, because the mean of its divisors is an integer number (30684127761517).
Almost surely, 261368255523033 is an apocalyptic number.
It is an amenable number.
61368255523033 is a deficient number, since it is larger than the sum of its proper divisors (1).
61368255523033 is an equidigital number, since it uses as much as digits as its factorization.
61368255523033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664000, while the sum is 52.
The spelling of 61368255523033 in words is "sixty-one trillion, three hundred sixty-eight billion, two hundred fifty-five million, five hundred twenty-three thousand, thirty-three".
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