Base | Representation |
---|---|
bin | 11011111010000011010010… |
… | …00100100010110111001011 |
3 | 22001021202012020112212021211 |
4 | 31331001221010202313023 |
5 | 31020424141403234144 |
6 | 334304104250513551 |
7 | 15632465403125563 |
oct | 1575015104426713 |
9 | 261252166485254 |
10 | 61368255524299 |
11 | 18610149415a09 |
12 | 6a716b47358b7 |
13 | 2832003870c19 |
14 | 112234cd55da3 |
15 | 7164e0d9c034 |
hex | 37d069122dcb |
61368255524299 has 2 divisors, whose sum is σ = 61368255524300. Its totient is φ = 61368255524298.
The previous prime is 61368255524273. The next prime is 61368255524321. The reversal of 61368255524299 is 99242555286316.
61368255524299 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61368255524299 - 213 = 61368255516107 is a prime.
It is not a weakly prime, because it can be changed into another prime (61368255524999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30684127762149 + 30684127762150.
It is an arithmetic number, because the mean of its divisors is an integer number (30684127762150).
Almost surely, 261368255524299 is an apocalyptic number.
61368255524299 is a deficient number, since it is larger than the sum of its proper divisors (1).
61368255524299 is an equidigital number, since it uses as much as digits as its factorization.
61368255524299 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 279936000, while the sum is 67.
The spelling of 61368255524299 in words is "sixty-one trillion, three hundred sixty-eight billion, two hundred fifty-five million, five hundred twenty-four thousand, two hundred ninety-nine".
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