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613875049436881 is a prime number
BaseRepresentation
bin1000101110010100001110110…
…0010000100001011011010001
32222111112212210200021212001201
42023211003230100201123101
51120430212100123440011
610013334145435231201
7243206002664441551
oct21345035420413321
92874485720255051
10613875049436881
11168665a45799131
1258a2511bba8501
132046c226a3690b
14ab839d4ac1161
154ae84736c6cc1
hex22e50ec4216d1

613875049436881 has 2 divisors, whose sum is σ = 613875049436882. Its totient is φ = 613875049436880.

The previous prime is 613875049436821. The next prime is 613875049436897. The reversal of 613875049436881 is 188634940578316.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 437136769889856 + 176738279547025 = 20907816^2 + 13294295^2 .

It is a cyclic number.

It is not a de Polignac number, because 613875049436881 - 241 = 611676026181329 is a prime.

It is a super-2 number, since 2×6138750494368812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (613875049436821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306937524718440 + 306937524718441.

It is an arithmetic number, because the mean of its divisors is an integer number (306937524718441).

Almost surely, 2613875049436881 is an apocalyptic number.

It is an amenable number.

613875049436881 is a deficient number, since it is larger than the sum of its proper divisors (1).

613875049436881 is an equidigital number, since it uses as much as digits as its factorization.

613875049436881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 836075520, while the sum is 73.

The spelling of 613875049436881 in words is "six hundred thirteen trillion, eight hundred seventy-five billion, forty-nine million, four hundred thirty-six thousand, eight hundred eighty-one".