Base | Representation |
---|---|
bin | 11011111110110110001111… |
… | …00110100011000101001001 |
3 | 22001212111120001220111102222 |
4 | 31333123013212203011021 |
5 | 31031124141331104031 |
6 | 334511520521503425 |
7 | 15650421230200541 |
oct | 1577330746430511 |
9 | 261774501814388 |
10 | 61533050253641 |
11 | 186740247831aa |
12 | 6a99626041b75 |
13 | 28447072880a5 |
14 | 112a303576321 |
15 | 71a938744e7b |
hex | 37f6c79a3149 |
61533050253641 has 2 divisors, whose sum is σ = 61533050253642. Its totient is φ = 61533050253640.
The previous prime is 61533050253551. The next prime is 61533050253677. The reversal of 61533050253641 is 14635205033516.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55974772493641 + 5558277760000 = 7481629^2 + 2357600^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61533050253641 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 61533050253592 and 61533050253601.
It is not a weakly prime, because it can be changed into another prime (61533050259641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30766525126820 + 30766525126821.
It is an arithmetic number, because the mean of its divisors is an integer number (30766525126821).
Almost surely, 261533050253641 is an apocalyptic number.
It is an amenable number.
61533050253641 is a deficient number, since it is larger than the sum of its proper divisors (1).
61533050253641 is an equidigital number, since it uses as much as digits as its factorization.
61533050253641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 44.
The spelling of 61533050253641 in words is "sixty-one trillion, five hundred thirty-three billion, fifty million, two hundred fifty-three thousand, six hundred forty-one".
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