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61593801377 is a prime number
BaseRepresentation
bin111001010111010001…
…101101001010100001
312212222120121022012212
4321113101231022201
52002121003121002
644143520531505
74310231446643
oct712721551241
9185876538185
1061593801377
1124138105689
12bb2b780b95
135a67a02724
142da4412893
15190762a352
hexe5746d2a1

61593801377 has 2 divisors, whose sum is σ = 61593801378. Its totient is φ = 61593801376.

The previous prime is 61593801341. The next prime is 61593801403. The reversal of 61593801377 is 77310839516.

61593801377 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56076134416 + 5517666961 = 236804^2 + 74281^2 .

It is a cyclic number.

It is not a de Polignac number, because 61593801377 - 28 = 61593801121 is a prime.

It is a super-2 number, since 2×615938013772 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (61593801337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30796900688 + 30796900689.

It is an arithmetic number, because the mean of its divisors is an integer number (30796900689).

Almost surely, 261593801377 is an apocalyptic number.

It is an amenable number.

61593801377 is a deficient number, since it is larger than the sum of its proper divisors (1).

61593801377 is an equidigital number, since it uses as much as digits as its factorization.

61593801377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 952560, while the sum is 50.

The spelling of 61593801377 in words is "sixty-one billion, five hundred ninety-three million, eight hundred one thousand, three hundred seventy-seven".