Base | Representation |
---|---|
bin | 101101001101111101110… |
… | …0111001001010101110111 |
3 | 211000010100012100201221210 |
4 | 1122123323213021111313 |
5 | 1303310243434144421 |
6 | 21115003005212503 |
7 | 1211000102563566 |
oct | 132337347112567 |
9 | 24003305321853 |
10 | 6214744053111 |
11 | 1a86726aaaa10 |
12 | 844561261133 |
13 | 361081182849 |
14 | 176b1c10bbdd |
15 | ab9d6a15576 |
hex | 5a6fb9c9577 |
6214744053111 has 32 divisors (see below), whose sum is σ = 9671387777280. Its totient is φ = 3509777779200.
The previous prime is 6214744053101. The next prime is 6214744053113. The reversal of 6214744053111 is 1113504474126.
It is not a de Polignac number, because 6214744053111 - 29 = 6214744052599 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6214744053111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6214744053113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 81206610 + ... + 81283103.
It is an arithmetic number, because the mean of its divisors is an integer number (302230868040).
Almost surely, 26214744053111 is an apocalyptic number.
6214744053111 is a gapful number since it is divisible by the number (61) formed by its first and last digit.
6214744053111 is a deficient number, since it is larger than the sum of its proper divisors (3456643724169).
6214744053111 is a wasteful number, since it uses less digits than its factorization.
6214744053111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162489807.
The product of its (nonzero) digits is 80640, while the sum is 39.
The spelling of 6214744053111 in words is "six trillion, two hundred fourteen billion, seven hundred forty-four million, fifty-three thousand, one hundred eleven".
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