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625100664540433 is a prime number
BaseRepresentation
bin1000111000100001101001011…
…1000011110000110100010001
310000222022001002002120022010111
42032020122113003300310101
51123413122130110243213
610053251140401401321
7245445014125446334
oct21610322703606421
93028261062508114
10625100664540433
111711a3780879704
125a138843939241
1320aa4980269733
14b05106827a61b
154c40481ecaa3d
hex23886970f0d11

625100664540433 has 2 divisors, whose sum is σ = 625100664540434. Its totient is φ = 625100664540432.

The previous prime is 625100664540377. The next prime is 625100664540563. The reversal of 625100664540433 is 334045466001526.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 620693045618944 + 4407618921489 = 24913712^2 + 2099433^2 .

It is a cyclic number.

It is not a de Polignac number, because 625100664540433 - 233 = 625092074605841 is a prime.

It is not a weakly prime, because it can be changed into another prime (625100664540733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312550332270216 + 312550332270217.

It is an arithmetic number, because the mean of its divisors is an integer number (312550332270217).

Almost surely, 2625100664540433 is an apocalyptic number.

It is an amenable number.

625100664540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

625100664540433 is an equidigital number, since it uses as much as digits as its factorization.

625100664540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6220800, while the sum is 49.

The spelling of 625100664540433 in words is "six hundred twenty-five trillion, one hundred billion, six hundred sixty-four million, five hundred forty thousand, four hundred thirty-three".