Base | Representation |
---|---|
bin | 10010001101011101010… |
… | …01110001010001101011 |
3 | 2012211001010202211210111 |
4 | 21012232221301101223 |
5 | 40222413303140433 |
6 | 1155235351555151 |
7 | 63130304004661 |
oct | 11065651612153 |
9 | 2184033684714 |
10 | 625700443243 |
11 | 2213a3651a37 |
12 | a132198bab7 |
13 | 47007329a85 |
14 | 223d967cc31 |
15 | 1142129ddcd |
hex | 91aea7146b |
625700443243 has 2 divisors, whose sum is σ = 625700443244. Its totient is φ = 625700443242.
The previous prime is 625700443217. The next prime is 625700443279. The reversal of 625700443243 is 342344007526.
625700443243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 625700443243 - 25 = 625700443211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 625700443196 and 625700443205.
It is not a weakly prime, because it can be changed into another prime (625700453243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312850221621 + 312850221622.
It is an arithmetic number, because the mean of its divisors is an integer number (312850221622).
Almost surely, 2625700443243 is an apocalyptic number.
625700443243 is a deficient number, since it is larger than the sum of its proper divisors (1).
625700443243 is an equidigital number, since it uses as much as digits as its factorization.
625700443243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 40.
The spelling of 625700443243 in words is "six hundred twenty-five billion, seven hundred million, four hundred forty-three thousand, two hundred forty-three".
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