Base | Representation |
---|---|
bin | 111010101101100000… |
… | …101101010000001001 |
3 | 20000201101221222210121 |
4 | 322231200231100021 |
5 | 2013101341340343 |
6 | 44543242143241 |
7 | 4361130020212 |
oct | 725540552011 |
9 | 200641858717 |
10 | 63040574473 |
11 | 2480a840728 |
12 | 102741b1b21 |
13 | 5c38679896 |
14 | 30a061c409 |
15 | 198e65daed |
hex | ead82d409 |
63040574473 has 2 divisors, whose sum is σ = 63040574474. Its totient is φ = 63040574472.
The previous prime is 63040574369. The next prime is 63040574503. The reversal of 63040574473 is 37447504036.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33836498809 + 29204075664 = 183947^2 + 170892^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-63040574473 is a prime.
It is a super-2 number, since 2×630405744732 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (63040574273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31520287236 + 31520287237.
It is an arithmetic number, because the mean of its divisors is an integer number (31520287237).
Almost surely, 263040574473 is an apocalyptic number.
It is an amenable number.
63040574473 is a deficient number, since it is larger than the sum of its proper divisors (1).
63040574473 is an equidigital number, since it uses as much as digits as its factorization.
63040574473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 846720, while the sum is 43.
The spelling of 63040574473 in words is "sixty-three billion, forty million, five hundred seventy-four thousand, four hundred seventy-three".
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