Base | Representation |
---|---|
bin | 11100101100100101011000… |
… | …11000110111101000001001 |
3 | 22021102201212201011010110201 |
4 | 32112102230120313220021 |
5 | 31232401110214311124 |
6 | 342113455244012201 |
7 | 16202103422203252 |
oct | 1626225430675011 |
9 | 267381781133421 |
10 | 63104551713289 |
11 | 1911a5433454a9 |
12 | 70b2102831061 |
13 | 292996cbcc7a8 |
14 | 11823c2dbbb29 |
15 | 746762e37144 |
hex | 3964ac637a09 |
63104551713289 has 2 divisors, whose sum is σ = 63104551713290. Its totient is φ = 63104551713288.
The previous prime is 63104551713241. The next prime is 63104551713311. The reversal of 63104551713289 is 98231715540136.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39564666102025 + 23539885611264 = 6290045^2 + 4851792^2 .
It is a cyclic number.
It is not a de Polignac number, because 63104551713289 - 235 = 63070191974921 is a prime.
It is not a weakly prime, because it can be changed into another prime (63104551713089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31552275856644 + 31552275856645.
It is an arithmetic number, because the mean of its divisors is an integer number (31552275856645).
It is a 2-persistent number, because it is pandigital, and so is 2⋅63104551713289 = 126209103426578, but 3⋅63104551713289 = 189313655139867 is not.
Almost surely, 263104551713289 is an apocalyptic number.
It is an amenable number.
63104551713289 is a deficient number, since it is larger than the sum of its proper divisors (1).
63104551713289 is an equidigital number, since it uses as much as digits as its factorization.
63104551713289 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 55.
The spelling of 63104551713289 in words is "sixty-three trillion, one hundred four billion, five hundred fifty-one million, seven hundred thirteen thousand, two hundred eighty-nine".
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