Base | Representation |
---|---|
bin | 11100101100101010000100… |
… | …00010111011011010101001 |
3 | 22021102222100200201112202021 |
4 | 32112111002002323122221 |
5 | 31232421231002402131 |
6 | 342114552335504441 |
7 | 16202222561001445 |
oct | 1626250202733251 |
9 | 267388320645667 |
10 | 63107062544041 |
11 | 1912061167683a |
12 | 70b26a3688121 |
13 | 2929c80151969 |
14 | 118258064b825 |
15 | 74685d5a1e11 |
hex | 3965420bb6a9 |
63107062544041 has 2 divisors, whose sum is σ = 63107062544042. Its totient is φ = 63107062544040.
The previous prime is 63107062544017. The next prime is 63107062544089. The reversal of 63107062544041 is 14044526070136.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42881490172816 + 20225572371225 = 6548396^2 + 4497285^2 .
It is a cyclic number.
It is not a de Polignac number, because 63107062544041 - 237 = 62969623590569 is a prime.
It is not a weakly prime, because it can be changed into another prime (63107062544011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31553531272020 + 31553531272021.
It is an arithmetic number, because the mean of its divisors is an integer number (31553531272021).
Almost surely, 263107062544041 is an apocalyptic number.
It is an amenable number.
63107062544041 is a deficient number, since it is larger than the sum of its proper divisors (1).
63107062544041 is an equidigital number, since it uses as much as digits as its factorization.
63107062544041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 63107062544041 in words is "sixty-three trillion, one hundred seven billion, sixty-two million, five hundred forty-four thousand, forty-one".
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