Base | Representation |
---|---|
bin | 10010011000010010001… |
… | …11010011111100001111 |
3 | 2020101001020022121112112 |
4 | 21030021013103330033 |
5 | 40321314323313033 |
6 | 1202040233254235 |
7 | 63424324550135 |
oct | 11141107237417 |
9 | 2211036277475 |
10 | 631513104143 |
11 | 223906758119 |
12 | a248456437b |
13 | 477226522ac |
14 | 227cb643755 |
15 | 1166172dc48 |
hex | 93091d3f0f |
631513104143 has 4 divisors (see below), whose sum is σ = 664750635960. Its totient is φ = 598275572328.
The previous prime is 631513104139. The next prime is 631513104163. The reversal of 631513104143 is 341401315136.
631513104143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 631513104143 - 22 = 631513104139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (631513104163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16618765880 + ... + 16618765917.
It is an arithmetic number, because the mean of its divisors is an integer number (166187658990).
Almost surely, 2631513104143 is an apocalyptic number.
631513104143 is a deficient number, since it is larger than the sum of its proper divisors (33237531817).
631513104143 is a wasteful number, since it uses less digits than its factorization.
631513104143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33237531816.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 631513104143 its reverse (341401315136), we get a palindrome (972914419279).
The spelling of 631513104143 in words is "six hundred thirty-one billion, five hundred thirteen million, one hundred four thousand, one hundred forty-three".
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