Base | Representation |
---|---|
bin | 11100110011011100101101… |
… | …00100000100000000010001 |
3 | 22022021021122222210000101102 |
4 | 32121232112210010000101 |
5 | 31300232124120000342 |
6 | 342414103154514145 |
7 | 16225123243013213 |
oct | 1631562644040021 |
9 | 268237588700342 |
10 | 63340408750097 |
11 | 19200575505116 |
12 | 712b966895955 |
13 | 2945c89b757bb |
14 | 118d9993405b3 |
15 | 74c9692cd832 |
hex | 399b96904011 |
63340408750097 has 2 divisors, whose sum is σ = 63340408750098. Its totient is φ = 63340408750096.
The previous prime is 63340408750081. The next prime is 63340408750147. The reversal of 63340408750097 is 79005780404336.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40568033444416 + 22772375305681 = 6369304^2 + 4772041^2 .
It is a cyclic number.
It is not a de Polignac number, because 63340408750097 - 24 = 63340408750081 is a prime.
It is not a weakly prime, because it can be changed into another prime (63340408752097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31670204375048 + 31670204375049.
It is an arithmetic number, because the mean of its divisors is an integer number (31670204375049).
Almost surely, 263340408750097 is an apocalyptic number.
It is an amenable number.
63340408750097 is a deficient number, since it is larger than the sum of its proper divisors (1).
63340408750097 is an equidigital number, since it uses as much as digits as its factorization.
63340408750097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15240960, while the sum is 56.
The spelling of 63340408750097 in words is "sixty-three trillion, three hundred forty billion, four hundred eight million, seven hundred fifty thousand, ninety-seven".
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