Base | Representation |
---|---|
bin | 101110001001101111100… |
… | …0100000100000110011101 |
3 | 211110101200112021110200112 |
4 | 1130103133010010012131 |
5 | 1312411144203112222 |
6 | 21253553021135405 |
7 | 1223163165233333 |
oct | 134233704040635 |
9 | 24411615243615 |
10 | 6343114113437 |
11 | 2026110609262 |
12 | 8654080ba565 |
13 | 3701cb46ac1a |
14 | 17d018d2bb53 |
15 | aeeeb713be2 |
hex | 5c4df10419d |
6343114113437 has 4 divisors (see below), whose sum is σ = 6343133573340. Its totient is φ = 6343094653536.
The previous prime is 6343114113379. The next prime is 6343114113439. The reversal of 6343114113437 is 7343114113436.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3022796027161 + 3320318086276 = 1738619^2 + 1822174^2 .
It is a cyclic number.
It is not a de Polignac number, because 6343114113437 - 28 = 6343114113181 is a prime.
It is a super-3 number, since 3×63431141134373 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 6343114113394 and 6343114113403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6343114113439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9232538 + ... + 9895755.
It is an arithmetic number, because the mean of its divisors is an integer number (1585783393335).
Almost surely, 26343114113437 is an apocalyptic number.
It is an amenable number.
6343114113437 is a deficient number, since it is larger than the sum of its proper divisors (19459903).
6343114113437 is a wasteful number, since it uses less digits than its factorization.
6343114113437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19459902.
The product of its digits is 217728, while the sum is 41.
Subtracting 6343114113437 from its reverse (7343114113436), we obtain a palindrome (999999999999).
The spelling of 6343114113437 in words is "six trillion, three hundred forty-three billion, one hundred fourteen million, one hundred thirteen thousand, four hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •