Base | Representation |
---|---|
bin | 101110001001101111100… |
… | …0100000100000110011111 |
3 | 211110101200112021110200121 |
4 | 1130103133010010012133 |
5 | 1312411144203112224 |
6 | 21253553021135411 |
7 | 1223163165233335 |
oct | 134233704040637 |
9 | 24411615243617 |
10 | 6343114113439 |
11 | 2026110609264 |
12 | 8654080ba567 |
13 | 3701cb46ac1c |
14 | 17d018d2bb55 |
15 | aeeeb713be4 |
hex | 5c4df10419f |
6343114113439 has 2 divisors, whose sum is σ = 6343114113440. Its totient is φ = 6343114113438.
The previous prime is 6343114113379. The next prime is 6343114113443. The reversal of 6343114113439 is 9343114113436.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6343114113439 - 27 = 6343114113311 is a prime.
It is a super-2 number, since 2×63431141134392 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6343114113395 and 6343114113404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6343117113439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3171557056719 + 3171557056720.
It is an arithmetic number, because the mean of its divisors is an integer number (3171557056720).
Almost surely, 26343114113439 is an apocalyptic number.
6343114113439 is a deficient number, since it is larger than the sum of its proper divisors (1).
6343114113439 is an equidigital number, since it uses as much as digits as its factorization.
6343114113439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 279936, while the sum is 43.
The spelling of 6343114113439 in words is "six trillion, three hundred forty-three billion, one hundred fourteen million, one hundred thirteen thousand, four hundred thirty-nine".
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