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634713123857 is a prime number
BaseRepresentation
bin10010011110001111101…
…10011010110000010001
32020200022020201110100012
421033013312122300101
540344343024430412
61203325545004305
763566532351521
oct11170766326021
92220266643305
10634713123857
112251a901430a
12a3018183695
1347b125c9a97
1422a12635681
151179c632c22
hex93c7d9ac11

634713123857 has 2 divisors, whose sum is σ = 634713123858. Its totient is φ = 634713123856.

The previous prime is 634713123823. The next prime is 634713123881. The reversal of 634713123857 is 758321317436.

634713123857 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 423415695616 + 211297428241 = 650704^2 + 459671^2 .

It is a cyclic number.

It is not a de Polignac number, because 634713123857 - 232 = 630418156561 is a prime.

It is a super-3 number, since 3×6347131238573 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (634713123757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 317356561928 + 317356561929.

It is an arithmetic number, because the mean of its divisors is an integer number (317356561929).

Almost surely, 2634713123857 is an apocalyptic number.

It is an amenable number.

634713123857 is a deficient number, since it is larger than the sum of its proper divisors (1).

634713123857 is an equidigital number, since it uses as much as digits as its factorization.

634713123857 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2540160, while the sum is 50.

The spelling of 634713123857 in words is "six hundred thirty-four billion, seven hundred thirteen million, one hundred twenty-three thousand, eight hundred fifty-seven".