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63483139 is a prime number
BaseRepresentation
bin1111001000101…
…0110100000011
311102110021111101
43302022310003
5112222430024
610144355231
71400412016
oct362126403
9142407441
1063483139
113291a905
1219315b17
13101c94b5
14860737d
15588ec44
hex3c8ad03

63483139 has 2 divisors, whose sum is σ = 63483140. Its totient is φ = 63483138.

The previous prime is 63483113. The next prime is 63483149. The reversal of 63483139 is 93138436.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 63483139 - 213 = 63474947 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 63483098 and 63483107.

It is not a weakly prime, because it can be changed into another prime (63483149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31741569 + 31741570.

It is an arithmetic number, because the mean of its divisors is an integer number (31741570).

Almost surely, 263483139 is an apocalyptic number.

63483139 is a deficient number, since it is larger than the sum of its proper divisors (1).

63483139 is an equidigital number, since it uses as much as digits as its factorization.

63483139 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46656, while the sum is 37.

The square root of 63483139 is about 7967.6307017833. The cubic root of 63483139 is about 398.9202944621.

The spelling of 63483139 in words is "sixty-three million, four hundred eighty-three thousand, one hundred thirty-nine".