Base | Representation |
---|---|
bin | 111011001000111001… |
… | …110010000101001001 |
3 | 20001220102200222010222 |
4 | 323020321302011021 |
5 | 2020022013221211 |
6 | 45101020115425 |
7 | 4405410136106 |
oct | 731071620511 |
9 | 201812628128 |
10 | 63500132681 |
11 | 24a261955a7 |
12 | 10382095b75 |
13 | 5cac94200b |
14 | 3105687aad |
15 | 19b9b891db |
hex | ec8e72149 |
63500132681 has 2 divisors, whose sum is σ = 63500132682. Its totient is φ = 63500132680.
The previous prime is 63500132639. The next prime is 63500132713. The reversal of 63500132681 is 18623100536.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55272010000 + 8228122681 = 235100^2 + 90709^2 .
It is a cyclic number.
It is not a de Polignac number, because 63500132681 - 218 = 63499870537 is a prime.
It is a super-2 number, since 2×635001326812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (63500132611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31750066340 + 31750066341.
It is an arithmetic number, because the mean of its divisors is an integer number (31750066341).
Almost surely, 263500132681 is an apocalyptic number.
It is an amenable number.
63500132681 is a deficient number, since it is larger than the sum of its proper divisors (1).
63500132681 is an equidigital number, since it uses as much as digits as its factorization.
63500132681 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 63500132681 in words is "sixty-three billion, five hundred million, one hundred thirty-two thousand, six hundred eighty-one".
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