Base | Representation |
---|---|
bin | 101110001110000010100… |
… | …1101011111100101100001 |
3 | 211111021111210001001000012 |
4 | 1130130011031133211201 |
5 | 1313034100034212423 |
6 | 21302120534534305 |
7 | 1223641002362351 |
oct | 134340515374541 |
9 | 24437453031005 |
10 | 6352344054113 |
11 | 202a017682302 |
12 | 867163207395 |
13 | 37103c759495 |
14 | 17d652abab61 |
15 | b038bbb1078 |
hex | 5c70535f961 |
6352344054113 has 8 divisors (see below), whose sum is σ = 6551254668288. Its totient is φ = 6155759880144.
The previous prime is 6352344054107. The next prime is 6352344054131. The reversal of 6352344054113 is 3114504432536.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 6352344054113 - 216 = 6352343988577 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6352344024113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 581604506 + ... + 581615427.
It is an arithmetic number, because the mean of its divisors is an integer number (818906833536).
Almost surely, 26352344054113 is an apocalyptic number.
It is an amenable number.
6352344054113 is a deficient number, since it is larger than the sum of its proper divisors (198910614175).
6352344054113 is a wasteful number, since it uses less digits than its factorization.
6352344054113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1163220103.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 6352344054113 its reverse (3114504432536), we get a palindrome (9466848486649).
The spelling of 6352344054113 in words is "six trillion, three hundred fifty-two billion, three hundred forty-four million, fifty-four thousand, one hundred thirteen".
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