Base | Representation |
---|---|
bin | 101110001110000010100… |
… | …1101011000010000110001 |
3 | 211111021111202222111212002 |
4 | 1130130011031120100301 |
5 | 1313034100032232423 |
6 | 21302120534143345 |
7 | 1223641002206033 |
oct | 134340515302061 |
9 | 24437452874762 |
10 | 6352344024113 |
11 | 202a01766180a |
12 | 8671631b1b55 |
13 | 37103c748929 |
14 | 17d652aadc53 |
15 | b038bba7228 |
hex | 5c705358431 |
6352344024113 has 2 divisors, whose sum is σ = 6352344024114. Its totient is φ = 6352344024112.
The previous prime is 6352344024109. The next prime is 6352344024127. The reversal of 6352344024113 is 3114204432536.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5439847193104 + 912496831009 = 2332348^2 + 955247^2 .
It is a cyclic number.
It is not a de Polignac number, because 6352344024113 - 22 = 6352344024109 is a prime.
It is not a weakly prime, because it can be changed into another prime (6352344024413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3176172012056 + 3176172012057.
It is an arithmetic number, because the mean of its divisors is an integer number (3176172012057).
Almost surely, 26352344024113 is an apocalyptic number.
It is an amenable number.
6352344024113 is a deficient number, since it is larger than the sum of its proper divisors (1).
6352344024113 is an equidigital number, since it uses as much as digits as its factorization.
6352344024113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 6352344024113 its reverse (3114204432536), we get a palindrome (9466548456649).
The spelling of 6352344024113 in words is "six trillion, three hundred fifty-two billion, three hundred forty-four million, twenty-four thousand, one hundred thirteen".
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