Base | Representation |
---|---|
bin | 101110011000001000011… |
… | …0001100011111101011111 |
3 | 211120100102220210012200022 |
4 | 1130300100301203331133 |
5 | 1313412434300120241 |
6 | 21320103041222355 |
7 | 1225335660444653 |
oct | 134602061437537 |
9 | 24510386705608 |
10 | 6374012895071 |
11 | 2038227122228 |
12 | 86b3b00319bb |
13 | 3730b3ac0c73 |
14 | 18070a896a63 |
15 | b0c091c854b |
hex | 5cc10c63f5f |
6374012895071 has 4 divisors (see below), whose sum is σ = 6393269731944. Its totient is φ = 6354756058200.
The previous prime is 6374012895031. The next prime is 6374012895121. The reversal of 6374012895071 is 1705982104736.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6374012895071 - 210 = 6374012894047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6374012895011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9628417940 + ... + 9628418601.
It is an arithmetic number, because the mean of its divisors is an integer number (1598317432986).
It is a 1-persistent number, because it is pandigital, but 2⋅6374012895071 = 12748025790142 is not.
Almost surely, 26374012895071 is an apocalyptic number.
6374012895071 is a deficient number, since it is larger than the sum of its proper divisors (19256836873).
6374012895071 is a wasteful number, since it uses less digits than its factorization.
6374012895071 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19256836872.
The product of its (nonzero) digits is 2540160, while the sum is 53.
The spelling of 6374012895071 in words is "six trillion, three hundred seventy-four billion, twelve million, eight hundred ninety-five thousand, seventy-one".
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