Base | Representation |
---|---|
bin | 10010100101001111101… |
… | …00001111110100010001 |
3 | 2021001000010011121202211 |
4 | 21102213310033310101 |
5 | 40430041441314103 |
6 | 1205150453512121 |
7 | 64061616663556 |
oct | 11224764176421 |
9 | 2231003147684 |
10 | 638470651153 |
11 | 226857046175 |
12 | a38a6642641 |
13 | 48290c1300a |
14 | 22c8b6aca2d |
15 | 1191c45e36d |
hex | 94a7d0fd11 |
638470651153 has 2 divisors, whose sum is σ = 638470651154. Its totient is φ = 638470651152.
The previous prime is 638470651099. The next prime is 638470651157. The reversal of 638470651153 is 351156074836.
638470651153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 398182454289 + 240288196864 = 631017^2 + 490192^2 .
It is a cyclic number.
It is not a de Polignac number, because 638470651153 - 217 = 638470520081 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 638470651097 and 638470651106.
It is not a weakly prime, because it can be changed into another prime (638470651157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 319235325576 + 319235325577.
It is an arithmetic number, because the mean of its divisors is an integer number (319235325577).
Almost surely, 2638470651153 is an apocalyptic number.
It is an amenable number.
638470651153 is a deficient number, since it is larger than the sum of its proper divisors (1).
638470651153 is an equidigital number, since it uses as much as digits as its factorization.
638470651153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 638470651153 in words is "six hundred thirty-eight billion, four hundred seventy million, six hundred fifty-one thousand, one hundred fifty-three".
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