Base | Representation |
---|---|
bin | 111011011101110100… |
… | …001100011001000001 |
3 | 20002210212220022200221 |
4 | 323131310030121001 |
5 | 2021231323122441 |
6 | 45155512143041 |
7 | 4420200311143 |
oct | 733564143101 |
9 | 202725808627 |
10 | 63850989121 |
11 | 250962451a7 |
12 | 1045b697a81 |
13 | 6037537c8a |
14 | 313a0d8c93 |
15 | 19da8918d1 |
hex | eddd0c641 |
63850989121 has 2 divisors, whose sum is σ = 63850989122. Its totient is φ = 63850989120.
The previous prime is 63850989109. The next prime is 63850989127. The reversal of 63850989121 is 12198905836.
63850989121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49035230721 + 14815758400 = 221439^2 + 121720^2 .
It is a cyclic number.
It is not a de Polignac number, because 63850989121 - 221 = 63848891969 is a prime.
It is not a weakly prime, because it can be changed into another prime (63850989127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31925494560 + 31925494561.
It is an arithmetic number, because the mean of its divisors is an integer number (31925494561).
Almost surely, 263850989121 is an apocalyptic number.
It is an amenable number.
63850989121 is a deficient number, since it is larger than the sum of its proper divisors (1).
63850989121 is an equidigital number, since it uses as much as digits as its factorization.
63850989121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 52.
The spelling of 63850989121 in words is "sixty-three billion, eight hundred fifty million, nine hundred eighty-nine thousand, one hundred twenty-one".
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