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63930102937 is a prime number
BaseRepresentation
bin111011100010100001…
…111111010010011001
320010000101202201110021
4323202201333102121
52021412101243222
645211415550441
74422150623521
oct734241772231
9203011681407
1063930102937
1125126970618
121048208b421
13604aa47b9c
143146810681
1519e27bcac7
hexee287f499

63930102937 has 2 divisors, whose sum is σ = 63930102938. Its totient is φ = 63930102936.

The previous prime is 63930102881. The next prime is 63930102941. The reversal of 63930102937 is 73920103936.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43415556496 + 20514546441 = 208364^2 + 143229^2 .

It is a cyclic number.

It is not a de Polignac number, because 63930102937 - 235 = 29570364569 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 63930102893 and 63930102902.

It is not a weakly prime, because it can be changed into another prime (63930102967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31965051468 + 31965051469.

It is an arithmetic number, because the mean of its divisors is an integer number (31965051469).

Almost surely, 263930102937 is an apocalyptic number.

It is an amenable number.

63930102937 is a deficient number, since it is larger than the sum of its proper divisors (1).

63930102937 is an equidigital number, since it uses as much as digits as its factorization.

63930102937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 183708, while the sum is 43.

Subtracting 63930102937 from its reverse (73920103936), we obtain a palindrome (9990000999).

The spelling of 63930102937 in words is "sixty-three billion, nine hundred thirty million, one hundred two thousand, nine hundred thirty-seven".