Base | Representation |
---|---|
bin | 11101000100101001101011… |
… | …11010110111100010011011 |
3 | 22101100210100122202011021121 |
4 | 32202110311322313202123 |
5 | 31334423144130401433 |
6 | 343545420005550111 |
7 | 16315616663525221 |
oct | 1642246572674233 |
9 | 271323318664247 |
10 | 63931492825243 |
11 | 1940921501137a |
12 | 7206427715337 |
13 | 29899385abc14 |
14 | 11b042d416b11 |
15 | 75d01152ac2d |
hex | 3a2535eb789b |
63931492825243 has 2 divisors, whose sum is σ = 63931492825244. Its totient is φ = 63931492825242.
The previous prime is 63931492825139. The next prime is 63931492825247. The reversal of 63931492825243 is 34252829413936.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 63931492825243 - 241 = 61732469569691 is a prime.
It is a super-2 number, since 2×639314928252432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (63931492825247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31965746412621 + 31965746412622.
It is an arithmetic number, because the mean of its divisors is an integer number (31965746412622).
Almost surely, 263931492825243 is an apocalyptic number.
63931492825243 is a deficient number, since it is larger than the sum of its proper divisors (1).
63931492825243 is an equidigital number, since it uses as much as digits as its factorization.
63931492825243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 67184640, while the sum is 61.
The spelling of 63931492825243 in words is "sixty-three trillion, nine hundred thirty-one billion, four hundred ninety-two million, eight hundred twenty-five thousand, two hundred forty-three".
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