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639800521113553 is a prime number
BaseRepresentation
bin1001000101111001010010101…
…0110010011011111111010001
310002220100022222101002210221021
42101132110222302123333101
51132324442431401113203
610144424145103555441
7251523030230631322
oct22136245262337721
93086308871083837
10639800521113553
11175950971670178
125b911763bbbb81
13215ccc12a20527
14b3dc720956449
154de7a2e59e5bd
hex245e52ac9bfd1

639800521113553 has 2 divisors, whose sum is σ = 639800521113554. Its totient is φ = 639800521113552.

The previous prime is 639800521113541. The next prime is 639800521113641. The reversal of 639800521113553 is 355311125008936.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 335411679805504 + 304388841308049 = 18314248^2 + 17446743^2 .

It is a cyclic number.

It is not a de Polignac number, because 639800521113553 - 217 = 639800520982481 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 639800521113553.

It is not a weakly prime, because it can be changed into another prime (639800521113353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 319900260556776 + 319900260556777.

It is an arithmetic number, because the mean of its divisors is an integer number (319900260556777).

Almost surely, 2639800521113553 is an apocalyptic number.

It is an amenable number.

639800521113553 is a deficient number, since it is larger than the sum of its proper divisors (1).

639800521113553 is an equidigital number, since it uses as much as digits as its factorization.

639800521113553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916000, while the sum is 52.

The spelling of 639800521113553 in words is "six hundred thirty-nine trillion, eight hundred billion, five hundred twenty-one million, one hundred thirteen thousand, five hundred fifty-three".