6400211131 has 2 divisors, whose sum is σ = 6400211132. Its totient is φ = 6400211130.

The previous prime is 6400211089. The next prime is 6400211141. The reversal of 6400211131 is 1311120046.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6400211131 - 2¹¹ = 6400209083 is a prime.

It is a super-2 number, since 2×6400211131² = 81925405042752598322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6400211099 and 6400211108.

It is not a weakly prime, because it can be changed into another prime (6400211141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3200105565 + 3200105566.

It is an arithmetic number, because the mean of its divisors is an integer number (3200105566).

Almost surely, 2^6400211131 is an apocalyptic number.

6400211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

6400211131 is an equidigital number, since it uses as much as digits as its factorization.

6400211131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 6400211131 is about 80001.3195578673. The cubic root of 6400211131 is about 1856.6559495392.

Adding to 6400211131 its reverse (1311120046), we get a palindrome (7711331177).

The spelling of 6400211131 in words is "six billion, four hundred million, two hundred eleven thousand, one hundred thirty-one".