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64100040433 = 1113768758313
BaseRepresentation
bin111011101100101010…
…001111111011110001
320010110020112102212121
4323230222033323301
52022234102243213
645240330154241
74426313232232
oct735452177361
9203406472777
1064100040433
1125203890130
121050ab82981
136077007910
143161209089
151a0268988d
hexeeca8fef1

64100040433 has 16 divisors (see below), whose sum is σ = 75317429376. Its totient is φ = 53782323840.

The previous prime is 64100040419. The next prime is 64100040469. The reversal of 64100040433 is 33404000146.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 64100040433 - 25 = 64100040401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 64100040398 and 64100040407.

It is not an unprimeable number, because it can be changed into a prime (64100041433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1070085 + ... + 1128397.

It is an arithmetic number, because the mean of its divisors is an integer number (4707339336).

Almost surely, 264100040433 is an apocalyptic number.

It is an amenable number.

64100040433 is a deficient number, since it is larger than the sum of its proper divisors (11217388943).

64100040433 is a wasteful number, since it uses less digits than its factorization.

64100040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66024.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 64100040433 its reverse (33404000146), we get a palindrome (97504040579).

The spelling of 64100040433 in words is "sixty-four billion, one hundred million, forty thousand, four hundred thirty-three".

Divisors: 1 11 13 143 7687 58313 84557 99931 641443 758069 1099241 8338759 448252031 4930772341 5827276403 64100040433