Base | Representation |
---|---|
bin | 11101001001101011110011… |
… | …10110001010011101100001 |
3 | 22101222022202000200112000221 |
4 | 32210311321312022131201 |
5 | 31400241333332301221 |
6 | 344201100310043041 |
7 | 16334251364100646 |
oct | 1644657166123541 |
9 | 271868660615027 |
10 | 64104431134561 |
11 | 1947559a1a3854 |
12 | 7233a50349481 |
13 | 29a00391cab6c |
14 | 11b89573d7dcd |
15 | 762783cd1541 |
hex | 3a4d79d8a761 |
64104431134561 has 2 divisors, whose sum is σ = 64104431134562. Its totient is φ = 64104431134560.
The previous prime is 64104431134543. The next prime is 64104431134589. The reversal of 64104431134561 is 16543113440146.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 61933358550625 + 2171072583936 = 7869775^2 + 1473456^2 .
It is a cyclic number.
It is not a de Polignac number, because 64104431134561 - 225 = 64104397580129 is a prime.
It is not a weakly prime, because it can be changed into another prime (64104431134501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32052215567280 + 32052215567281.
It is an arithmetic number, because the mean of its divisors is an integer number (32052215567281).
Almost surely, 264104431134561 is an apocalyptic number.
It is an amenable number.
64104431134561 is a deficient number, since it is larger than the sum of its proper divisors (1).
64104431134561 is an equidigital number, since it uses as much as digits as its factorization.
64104431134561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 64104431134561 in words is "sixty-four trillion, one hundred four billion, four hundred thirty-one million, one hundred thirty-four thousand, five hundred sixty-one".
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