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64113132 = 2235342761
BaseRepresentation
bin1111010010010…
…0100111101100
311110122021200110
43310210213230
5112403110012
610210100020
71405644516
oct364444754
9143567613
1064113132
1133210166
121957a610
131038a185
14872cbb6
15596673c
hex3d249ec

64113132 has 12 divisors (see below), whose sum is σ = 149597336. Its totient is φ = 21371040.

The previous prime is 64113107. The next prime is 64113139. The reversal of 64113132 is 23131146.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×641131322 = 8220987389698848, which contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 64113099 and 64113108.

It is not an unprimeable number, because it can be changed into a prime (64113139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2671369 + ... + 2671392.

Almost surely, 264113132 is an apocalyptic number.

It is an amenable number.

64113132 is an abundant number, since it is smaller than the sum of its proper divisors (85484204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

64113132 is a wasteful number, since it uses less digits than its factorization.

64113132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5342768 (or 5342766 counting only the distinct ones).

The product of its digits is 432, while the sum is 21.

The square root of 64113132 is about 8007.0676280396. The cubic root of 64113132 is about 400.2355529265.

Adding to 64113132 its reverse (23131146), we get a palindrome (87244278).

The spelling of 64113132 in words is "sixty-four million, one hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 5342761 10685522 16028283 21371044 32056566 64113132