Base | Representation |
---|---|
bin | 10010101010010110001… |
… | …10000010011001100001 |
3 | 2021022002000202000022022 |
4 | 21111023012002121201 |
5 | 41001144230012433 |
6 | 1210322351351225 |
7 | 64216532036342 |
oct | 11251306023141 |
9 | 2238060660268 |
10 | 641210000993 |
11 | 227a32369261 |
12 | a432bb22515 |
13 | 486095c6393 |
14 | 2306b4260c9 |
15 | 11a2cbb8698 |
hex | 954b182661 |
641210000993 has 2 divisors, whose sum is σ = 641210000994. Its totient is φ = 641210000992.
The previous prime is 641210000929. The next prime is 641210001037. The reversal of 641210000993 is 399000012146.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 558581348689 + 82628652304 = 747383^2 + 287452^2 .
It is a cyclic number.
It is not a de Polignac number, because 641210000993 - 26 = 641210000929 is a prime.
It is a super-2 number, since 2×6412100009932 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (641210000393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320605000496 + 320605000497.
It is an arithmetic number, because the mean of its divisors is an integer number (320605000497).
Almost surely, 2641210000993 is an apocalyptic number.
It is an amenable number.
641210000993 is a deficient number, since it is larger than the sum of its proper divisors (1).
641210000993 is an equidigital number, since it uses as much as digits as its factorization.
641210000993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 641210000993 in words is "six hundred forty-one billion, two hundred ten million, nine hundred ninety-three", and thus it is an aban number.
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