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6413009816761 is a prime number
BaseRepresentation
bin101110101010010010100…
…1011000000110010111001
3211201002002200101002102021
41131110211023000302321
51320032321003114021
621350032424434441
71231216235014132
oct135244513006271
924632080332367
106413009816761
112052818944729
12876a74018a21
1337698a0c9162
14182569b54c89
15b1c3cac1c41
hex5d5252c0cb9

6413009816761 has 2 divisors, whose sum is σ = 6413009816762. Its totient is φ = 6413009816760.

The previous prime is 6413009816749. The next prime is 6413009816777. The reversal of 6413009816761 is 1676189003146.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3539496636025 + 2873513180736 = 1881355^2 + 1695144^2 .

It is a cyclic number.

It is not a de Polignac number, because 6413009816761 - 25 = 6413009816729 is a prime.

It is a super-2 number, since 2×64130098167612 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6413009816699 and 6413009816708.

It is not a weakly prime, because it can be changed into another prime (6413009816461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3206504908380 + 3206504908381.

It is an arithmetic number, because the mean of its divisors is an integer number (3206504908381).

Almost surely, 26413009816761 is an apocalyptic number.

It is an amenable number.

6413009816761 is a deficient number, since it is larger than the sum of its proper divisors (1).

6413009816761 is an equidigital number, since it uses as much as digits as its factorization.

6413009816761 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 52.

The spelling of 6413009816761 in words is "six trillion, four hundred thirteen billion, nine million, eight hundred sixteen thousand, seven hundred sixty-one".